Definition and Examples of Zimbabwean English

Definition and Examples of Zimbabwean English Zimbabwean English is the variety of the English language spoken in the Republic of Zimbabwe, located in southern Africa. English is the primary language used in schools in Zimbabwe, but it is one of the 16 official languages in the country.   Examples and Observations: From Rhodesia to ZimbabweZimbabwe, earlier Southern Rhodesia, became a British colony in 1898. By 1923 it gained a measure of self-government and was part of the Federation of Rhodesia and Nyasaland from 1953 to 1963. Like South Africa, Southern Rhodesia had a settled white population, the leaders of whom opposed the notion of one man, one vote. In 1965, the white minority broke away from Britain but its Unilateral Declaration of Independence (UDI) was declared illegal. In 1980, general elections were held and Zimbabwe came into existence.(Loreto Todd and Ian F. Hancock, International English Usage. Routledge, 1986)Influences on  Zimbabwean EnglishRhodesian English is regarded as a fossil, non-productive dialect. Independence as a democratic republic under black majority rule in 1980 changed the social, economic and political conditions in which blacks and whites interacted in Zimbabwe; in this environment, it is appropriate to refer to the prevailing English dialect in the country as Zimbabwean English (ZimE) as it is a productive and changing variety. . . .The principal influences on Rhodesian English lexis are Afrikaans and Bantu (mainly chiShona and isiNdebele). The more informal the situation, the more likely it is is to encounter local expressions.(Susan Fitzmaurice, L1 Rhodesian English. The Lesser-Known Varieties of English, ed. by D. Schreier et al. Cambridge University Press, 2010) Characteristics of  Zimbabwean English[W]hite Zimbabweans perceive that their dialect of English is distinct from other southern African accents. They . . . refer to details of pronunciation and lexis in order to illustrate how their speech differs from British English on the one hand and South African English on the other. For example, informants will refer to the fact that lakker . . . is a Zimbabwean word. Actually, it is a loanword from Afrikaans lekker, nice, but it is pronounced in a specifically Zimbabwean way, namely with a more open front vowel: lakker  [là ¦kÉ™]  and without a final flapped [r]. Additionally, Zimbabwean English has unique lexical expressions, many of them dating from early colonial days, some adaptations or innovations, some loan translations. For example, the (now quite old-fashioned) approbatory adjective mush or mushy . . . nice may well have arisen out of the persistent misunderstanding of the Shona word musha  home, while shupa (v. and n.) worry, bother, hassle, is a borrowing from Fanagalo, the colonial pidgin used by whites. The verb chaya strike ( Shona tshaya) also occurs in Fanagalo. Thus white Zimbabweans . . . link their dialect to the matter of the identification with place and differentiate themselves from those from neighboring South Africa for instance.(Susan Fitzmaurice, History, Social Meaning, and Identity in the Spoken English of White Zimbabweans.  Developments in English: Expanding Electronic Evidence, ed. by  Irma Taavitsainen  et al. Cambridge University Press, 2015) English in ZimbabweEnglish is the official language of Zimbabwe, and much teaching in schools is also carried out in English, except in the case of the youngest Shomna- and Ndebele-speaking children. . . . The Zimbabwean English of the native anglophone population resembles very closely that of South Africa, but according to Wells (1982) it has never been systematically studied. Native English speakers make up less than 1 per cent of the total population of 11 million.(Peter Trudgill, Lesser-Known Varieties of English. Alternative Histories of English, ed. by R. J. Watts and P. Trudgill. Routledge, 2002) Also Known As: Rhodesian English

Chemistry Review of pOH Calculations

Chemistry Review of pOH Calculations Sometimes you are asked to calculate pOH rather than pH. Heres a review of the pOH definition and an example calculation. Acids, Bases, pH and pOH There are several ways to define acids and bases, but pH and pOH refer to hydrogen ion concentration and hydroxide ion concentration, respectively. The p in pH and pOH stands for negative logarithm of and is used to make it easier to work with extremely large or small values.  pH and pOH are only meaningful when applied to aqueous (water-based) solutions. When water dissociates it yields a hydrogen ion and a hydroxide. H2O ⇆ H OH- When calculating pOH, remember that [] refers to molarity, M. Kw [H][OH-] 1x10-14 at 25 °Cfor pure water [H] [OH-] 1x10-7Acidic Solution: [H] 1x10-7Basic Solution: [H] 1x10-7 How to Find pOH Using Calculations There are a few different formulas you can use to calculate pOH, the hydroxide ion concentration, or the pH (if you know pOH): pOH -log10[OH-][OH-] 10-pOHpOH pH 14 for any aqueous solution pOH Example Problems Find the [OH-] given the pH or pOH. You are given that the pH 4.5. pOH pH 14pOH 4.5 14pOH 14 - 4.5pOH 9.5 [OH-] 10-pOH[OH-] 10-9.5[OH-] 3.2 x 10-10 M Find the hydroxide ion concentration of a solution with a pOH of 5.90. pOH -log[OH-]5.90 -log[OH-]Because youre working with log, you can rewrite the equation to solve for the hydroxide ion concentration: [OH-] 10-5.90To solve this, use a scientific calculator and enter 5.90 and use the /- button to make it negative and then press the 10x key. On some calculators, you can simply take the inverse log of -5.90. [OH-] 1.25 x 10-6 M Find the pOH of a chemical solution if the hydroxide ion concentration is 4.22 x 10-5 M. pOH -log[OH-]pOH -log[4.22 x 10-5] To find this on a scientific calculator, enter 4.22 x 5 (make it negative using the /- key), press the 10x key, and press equal to get the number in scientific notation. Now press log. Remember your answer is the negative value (-) of this number.pOH - (-4.37)pOH 4.37 Understand Why pH + pOH = 14 Water, whether its on its own or part of an aqueous solution, undergoes self-ionization which can be represented by the equation: 2 H2O ⇆ H3O OH- Equilibrium forms between the unionized water and the hydronium (H3O) and hydroxide (OH-) ions. The expression for the equilibrium constant Kw is: Kw [H3O][OH-] Strictly speaking, this relationship is only valid for aqueous solutions at 25 °C because that is when the value of Kw is 1 x 10-14. If you take the log of both side of the equation: log  (1 x 10-14)  Ã‚  log  [H3O]  Ã‚  log  [OH-] (Remember, when numbers are multiplied, their logs are added.) log  (1 x 10-14)  Ã‚  -  14-  14  Ã‚  log[H3O]  Ã‚  log  [OH-] Multiplying both sides of the equation by -1: 14  Ã‚  -  log  [H3O]  -  log  [OH-] pH is defined as  -  log  [H3O] and pOH is defined as -log  [OH-], so the relation becomes: 14 pH - (-pOH)14 pH pOH